5x^2-20x+36=0

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Solution for 5x^2-20x+36=0 equation:


Simplifying
5x2 + -20x + 36 = 0

Reorder the terms:
36 + -20x + 5x2 = 0

Solving
36 + -20x + 5x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
5 the coefficient of the squared term: 

Divide each side by '5'.
7.2 + -4x + x2 = 0

Move the constant term to the right:

Add '-7.2' to each side of the equation.
7.2 + -4x + -7.2 + x2 = 0 + -7.2

Reorder the terms:
7.2 + -7.2 + -4x + x2 = 0 + -7.2

Combine like terms: 7.2 + -7.2 = 0.0
0.0 + -4x + x2 = 0 + -7.2
-4x + x2 = 0 + -7.2

Combine like terms: 0 + -7.2 = -7.2
-4x + x2 = -7.2

The x term is -4x.  Take half its coefficient (-2).
Square it (4) and add it to both sides.

Add '4' to each side of the equation.
-4x + 4 + x2 = -7.2 + 4

Reorder the terms:
4 + -4x + x2 = -7.2 + 4

Combine like terms: -7.2 + 4 = -3.2
4 + -4x + x2 = -3.2

Factor a perfect square on the left side:
(x + -2)(x + -2) = -3.2

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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